## Search found 19 matches

### Re: Math proof

Here is the corrected version of your proof. Let A, B, and C be sets. If f(x) is a 1 - 1 and onto mapping from A --> B and g(x) is a 1-1 and onto mapping from B --> C, show g(f(x)) is 1-1 and onto. PF: Let x be an element of C. Then we know that since g(x) is 1 - 1 and onto then there is exact...
on Sun Apr 27, 2008 4:08 pm

Forum: Math & Science
Topic: Math proof
Views: 33464

### Re: Permanent Programming 11

Why not just use a JavaScript and get rid of all the cookie problems?
on Sun Apr 27, 2008 12:24 pm

Forum: Programming
Topic: Permanent Programming 11
Views: 218580

### Re: Programming 8

I know.. I have already completed the mission
on Sun Apr 27, 2008 12:21 pm

Forum: Programming
Topic: Programming 8
Views: 58012

### Programming 3 luck

I just finished programming 3 an hour ago, but I don't like my brute force method. My running time varies from 3s to 500s depending on the given values, so I was lucky when I completed it. I want to know how other people have done.. Does someone want to describe their method or perhaps show me some ...
on Sat Apr 26, 2008 6:05 pm

Forum: Programming
Topic: Programming 3 luck
Views: 83444

### Re: Math proof

"n(n+1)/2 + (n+1)[(n+1)+1]/2" should be "n(n+1)/2 + (n+1)". Then continue: n(n+1)/2 + (n+1) = (n^2+3n+2)/2 = [(n+1)^2+(n+1)]/2 = (n+1)((n+1)+1)/2 I never liked induction in high school, but it isn't very difficult. I got inspired by your sum, so here is a sum for you. You know (f...
on Sat Apr 26, 2008 5:51 pm

Forum: Math & Science
Topic: Math proof
Views: 33464

### Re: Math proof

Very good ELorenz and Inferno96 . It's not allowed to divide by 0. Please tell me if it's too simple.. Here is the next "proof" (please give answers to both versions if you can): I suppose you know complex numbers. sqrt(a) means square root of a, sqrt(-1)=i. 1 = sqrt(1)*sqrt(1) = sqrt(1*1)...
on Sat Apr 26, 2008 3:57 pm

Forum: Math & Science
Topic: Math proof
Views: 33464

### Math proof

I can make some math proofs which are (obviously) wrong. Your mission is to find out why the proofs ain't correct. When someone have submitted a good explanation, I will give you a new one.. Let's start simple. x = y Divide by (x-y) x/(x-y) = y/(x-y) Subtract y/(x-y) x/(x-y) - y/(x-y) = 0 Write on s...
on Sat Apr 26, 2008 5:55 am

Forum: Math & Science
Topic: Math proof
Views: 33464

### Programming 8

It says "notice moo with !perm8", but moo doesn't respond. I've tried a lot of things, but none works:
PRIVMSG moo :!perm8
PRIVMSG #perm8 :!perm8
And it doesn't work with a non-bot either:
!perm8
/msg moo !perm8

Am I doing something wrong or have moo died?
on Fri Apr 25, 2008 2:04 pm

Forum: Programming
Topic: Programming 8
Views: 58012

### Re: Puzzle

I got two different solutions.
1: Alice is applied, Bob is pure, Charlie is insane, Dorothy is insane
2: Alice is applied, Bob is insane, Charlie is insane, Dorothy is applied
on Wed Apr 23, 2008 6:02 pm

Forum: Math & Science
Topic: Puzzle