Reason7194 wrote:Hello Everyone, i have a physics question.
On a parallel circuit, the given voltage is 36V. There are two resistors which link to the other side of the circuit. Those resistors (R1 and R2) are 21 and 24. Before the circuit reached the negative side of the battery, there is another another resistor called R3 which equals 62. What is the current after R3?
I thought I had to do this: R1+R2+R3 = RT, Amps = 36/RT, but i was wrong. why?
Goatboy wrote:Oh, that's simple. All you need to do is dedicate many years of your life to studying security.
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