Ext basic 4

[satanswrath]

{user types 6,7} BEGIN F.ake
var int as in
int var as in
out var int

I don't really understand here, is it:
var: int as in
int: var as in
out: var int

Doesnt it mean like:
variable integer as in
integer variable as in
output variable integer
this 'in' is probably something like 'input'?

Can anyone help me here.. I'm a bit confused(

[satanswrath]

Yep, same problem.. same confusing status xD

[MrJonn]

It's a bit hard to give hints on this one since there's a fine line between hint and massive spoiler. You have to have an open mind with it and not confuse yourself with other languages that follow similar patterns. Take a step back, and as the TV show 'Catchphrase' said, say what you see!

[vineetdhanawat]

I guess.. a hint would:

Concentrate on User Types

P.S: Sry if it turns to b a spoiler..

[Sm4R7_H4x0R]

[Edited by: Defience-answer removed!]


[Edited By: Monica]
[Edited By: Sm4R7H4x0R]
[Edited By: Sm4R7H4x0R]
[Edited By: Sm4R7H4x0R]
[Edited By: Sm4R7H4x0R]
[Edited By: Sm4R7H4x0R]

[Defience]

[Edited by: Defience-answer removed!]

Do not post spoilers or in this case, the answer!

[Sm4R7_H4x0R]

[Monica]

What are you so happy about?

You shouldn't be using smileys because you are warned for posting huge spoilers that were close to the answer.

[Defience]

Some people just don't get it

[neocontra]

--shakes head with disbelief--

Anyway...I'm not clear on what this "program" actually does.

The user is putting in 6 and 7, then the program is running
Then "var int as in" then "int var as in"....these lines are confusing me, cause I can't seem to figure out what the "function" is and what the "argument" is.
Then "out var int" makes deciphering the middle two lines even harder, cause it seems the order of func(arg1, ...etc) is flipped maybe? Also, how is it manipulating the input? (I know you can't tell me me that, but a hint or nudge would be nice).

I hope I didn't inadvertently post spoilers, cause if I have the answer already, I don't know what it is.