Physics Question

[Reason7194]

Hello Everyone, i have a physics question.

On a parallel circuit, the given voltage is 36V. There are two resistors which link to the other side of the circuit. Those resistors (R1 and R2) are 21 and 24. Before the circuit reached the negative side of the battery, there is another another resistor called R3 which equals 62. What is the current after R3?

I thought I had to do this: R1+R2+R3 = RT, Amps = 36/RT, but i was wrong. why?

[pretentious]

Hello Everyone, i have a physics question.

On a parallel circuit, the given voltage is 36V. There are two resistors which link to the other side of the circuit. Those resistors (R1 and R2) are 21 and 24. Before the circuit reached the negative side of the battery, there is another another resistor called R3 which equals 62. What is the current after R3?

I thought I had to do this: R1+R2+R3 = RT, Amps = 36/RT, but i was wrong. why?

Been a while since I've done this stuff but if i can recall, resistance in parallel is calculated as 1/r1 +1/r2 or something like that. If i read it right, you have two resistors in parallel and one in series, so there will be two calculations....I think

[Reason7194]

Ya, you have what you are thinking of the picture right. I just need more of a push than that, i still cant solve it

[pretentious]

http://www.wikihow.com/Calculate-Series-and-Parallel-Resistance
How's that?

[msbachman]

Pretentious answered it pretty well but I also found a good link I thought I'd share

[Reason7194]

Thanks guys, got the answer now.