exercise in logarithm

Mathematics and Science; the subtle and ubiquitous arts

exercise in logarithm

Post by JProgress on Tue Mar 25, 2014 9:51 am
([msg=80026]see exercise in logarithm[/msg])

ln x/2 = (ln x)/2. How could this be solved???
Progress, not perfection...
User avatar
JProgress
New User
New User
 
Posts: 22
Joined: Thu Feb 13, 2014 10:32 am
Blog: View Blog (0)


Re: exercise in logarithm

Post by nightmair on Thu Mar 27, 2014 8:55 am
([msg=80040]see Re: exercise in logarithm[/msg])

y* ln( x ) = ln( x^y ) , so
1/2 * ln( x ) = ln ( x^( 1/2 ) ) = ln( sqrt( x ) )

Put that into your exercise and you get:
ln (x/2) = ln( sqrt(x) )
x/2 = sqrt(x)
x^2 / 4 = x
x*x = 4*x
x = 4

Tell me if I'm wrong, but i think this is the correct answer.
nightmair
New User
New User
 
Posts: 4
Joined: Sat Aug 31, 2013 5:46 pm
Blog: View Blog (0)


Re: exercise in logarithm

Post by JProgress on Thu Mar 27, 2014 10:32 am
([msg=80041]see Re: exercise in logarithm[/msg])

Yes...i think that's write.Thanks!

-- Sat Mar 29, 2014 10:44 am --

and that's a good solution too:

ln x/2 = (lnx)/2
lnx - ln2 = (lnx)/2
2ln x - 2ln 2 = 2(lnx)/2
2ln x - ln 2^2 = ln x
2ln x - ln x = ln 4
ln x =ln 4
x=4
Progress, not perfection...
User avatar
JProgress
New User
New User
 
Posts: 22
Joined: Thu Feb 13, 2014 10:32 am
Blog: View Blog (0)



Return to Math & Science

Who is online

Users browsing this forum: No registered users and 0 guests