Copied & Paste this example from a page, getting errors(PHP)

Code: Select all: <html> <head></head> <body> <?php /* if the "submit" variable does not exist, the form has not been submitted - display initial page */ if (!isset($_POST['submit'])) { ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> Enter your age: <input name="age" size="2"> <input type="submit" name="submit" value="Go"> </form> <?php } else { /* if the "submit" variable exists, the form has been submitted - look for and process form data */ // display result $age = $_POST['age']; if ($age >= 21) { echo 'Come on in, we have alcohol and music awaiting you!'; } else { echo 'You're too young for this club, come back when you're a little older'; } } ?> </body> </html>

This is the code I copied and pasted from http://devzone.zend.com/node/view/id/628 and when I attempted to run it on Apache Server 2.2 (Using Php 5.0), I got this error

Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\allinone.php on line 25

I seen this error before when I forgot to add ; in, but from the limited knowledge I have from php, I don't see what's wrong with this. Any help?

Take a look at line 25:

Code: Select all: echo 'You're too young for this club, come back when you're a little older';

That string is enclosed by single quotes '
And the string itself uses single quotes aswell as apostrophes - they arent escaped, for that reason, they end the string.
PHP sees this:

Code: Select all: echo 'You'<not a string anymore, should be code>'re a little older';

Because "re too young..." is not syntactically correct there, it throws the error.

Try this:

Code: Select all: echo 'You\'re too young for this club, come back when you\'re a little older';

Escaping the ' with \ tells PHP that a special character follows, which is to be taken literally.
There are also other ways to solve that, but I guess you can figure them out yourself

BhaaL wrote:Take a look at line 25:

Code: Select all
echo 'You're too young for this club, come back when you're a little older';

That string is enclosed by single quotes '
And the string itself uses single quotes aswell as apostrophes - they arent escaped, for that reason, they end the string.
PHP sees this:

Code: Select all
echo 'You'<not a string anymore, should be code>'re a little older';

Because "re too young..." is not syntactically correct there, it throws the error.

Try this:

Code: Select all
echo 'You\'re too young for this club, come back when you\'re a little older';

Escaping the ' with \ tells PHP that a special character follows, which is to be taken literally.
There are also other ways to solve that, but I guess you can figure them out yourself

Thanks

$tutorialSites != "fools proof"

Lol had to say that >.<

BTW: I also liked how you explained it instead of slap me the answer like some people do. Thanks :3

also tried inserting double quotes (") instead of single quotes (') to state the beginning of the string also seems to work. Though it'll probably be less confusing to just add the \

Copied & Paste this example from a page, getting errors(PHP)

Copied & Paste this example from a page, getting errors(PHP)

Re: Copied & Paste this example from a page, getting errors(PHP)

Re: Copied & Paste this example from a page, getting errors(PHP)

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