javascript mission 3

Learn the basics of how to exploit JavaScript.

Re: javascript mission 3

Post by BuTTHeaD on Sat Feb 07, 2009 12:39 am
([msg=17487]see Re: javascript mission 3[/msg])

Well, i have everything besides the percentage part.
I'm doing it on paper, then i check it on the internet.
I get the same answer, and it still doesn't work.
I don't really know what the problem is.
BuTTHeaD
Experienced User
Experienced User
 
Posts: 52
Joined: Tue Jul 15, 2008 4:45 pm
Blog: View Blog (0)


Re: javascript mission 3

Post by tursia on Sat Feb 07, 2009 4:21 am
([msg=17500]see Re: javascript mission 3[/msg])

c41n wrote:Ok ok I got the best hint go look at extbasic 1 and think of how that is solved... which should be easy this took a sec I kept over thinking... so think of it this way I have a javascript that will help you understand what .length is .
So just put this in fire fox address bar "just this "
javascript: var str="I like pie";alert(str.length);
Which would make it come to 10 so now we know what length is... then x.length == moo so I bet you think its *anwser* but the length can be characters it doesn't even have to be numerable .


hi c4`n, i kind of understand what u mean by the "x.length == moo", but one question does the two space equal as a one space character or just equal as two characters.
tursia
New User
New User
 
Posts: 1
Joined: Sat Feb 07, 2009 4:00 am
Blog: View Blog (0)


Re: javascript mission 3

Post by adihaliem on Sat Feb 14, 2009 1:25 pm
([msg=17886]see Re: javascript mission 3[/msg])

I hope this is not a spoiler, but if it is, then please edit
For example :
if you get moo=8, doesn't mean 8=1 character, so the answer is 1.
but the answers can be any number depending on "x.length == moo"
adihaliem
New User
New User
 
Posts: 2
Joined: Wed Feb 11, 2009 10:02 am
Blog: View Blog (0)


Re: javascript mission 3

Post by haxor0720 on Wed Feb 18, 2009 3:17 am
([msg=18145]see Re: javascript mission 3[/msg])

i understand this mission very clearly, i know what its asking for also but i think the mission is messed up can some one that already completed this mission recheck it for me thanks
haxor0720
New User
New User
 
Posts: 1
Joined: Wed Feb 18, 2009 3:15 am
Blog: View Blog (0)


Re: javascript mission 3

Post by aNewHobby4me on Wed Feb 18, 2009 7:47 am
([msg=18151]see Re: javascript mission 3[/msg])

haxor0720 wrote:i understand this mission very clearly, i know what its asking for also but i think the mission is messed up can some one that already completed this mission recheck it for me thanks


Works for me---but I had to allow scripts (using Firefox with NoScript).
"To understand recursion you must first understand recursion."
aNewHobby4me
Poster
Poster
 
Posts: 185
Joined: Thu Jan 08, 2009 5:44 pm
Blog: View Blog (0)


Re: javascript mission 3

Post by Defience on Wed Feb 18, 2009 11:00 am
([msg=18165]see Re: javascript mission 3[/msg])

The mission works fine.
User avatar
Defience
Addict
Addict
 
Posts: 1265
Joined: Thu Jun 12, 2008 3:16 pm
Blog: View Blog (0)


Re: javascript mission 3

Post by here_comes_trouble on Tue Mar 03, 2009 2:04 am
([msg=19142]see Re: javascript mission 3[/msg])

I think it took me about an hour or more to figure this one out but it makes sense once you figure it out.
this defintally requires understanding of variables, operators and comparisions.
you just need to ask yourself what the section..
if (x.length == moo) means.

www.w3schools.com
theres your spoiler right there.
(theres not really a spoiler, idk what id do w.o w3 lol)
here_comes_trouble
New User
New User
 
Posts: 3
Joined: Thu Feb 26, 2009 2:41 am
Blog: View Blog (0)


Re: javascript mission 3

Post by BillySheehan on Tue Mar 03, 2009 3:40 am
([msg=19143]see Re: javascript mission 3[/msg])

Robbinski12 wrote:just enter all the calculations from the textarea in the adressbar

example:

javascript:var r=3*4; var o=r/2; alert(o)
copy and paste it in ur adressbar, it will give 6



I'd just like to say that this bit was amazing. thanks!
"Atheism is a non-prophet organization." - George Carlin (RIP)
BillySheehan
New User
New User
 
Posts: 1
Joined: Tue Mar 03, 2009 3:36 am
Blog: View Blog (0)


Re: javascript mission 3

Post by vesopeso on Tue Mar 03, 2009 7:33 am
([msg=19145]see Re: javascript mission 3[/msg])

I've done all of the JavaScript and i would say that they are pretty easy you just have to know JavaScript and read CAREFULLY !!! ;)
vesopeso
New User
New User
 
Posts: 12
Joined: Sat Jan 10, 2009 3:46 pm
Blog: View Blog (0)


Re: javascript mission 3

Post by eudincanada on Fri Mar 13, 2009 3:15 pm
([msg=19911]see Re: javascript mission 3[/msg])

OMG I just finished and I feel like a stupid ****. It's way easyer than you think it's all about the x.length just think in english what that means... That the ****** of x = moo.
eudincanada
New User
New User
 
Posts: 2
Joined: Fri Mar 13, 2009 3:12 pm
Blog: View Blog (0)


PreviousNext

Return to Javascript

Who is online

Users browsing this forum: No registered users and 0 guests