Error msg:Permission denied, Id returned 1 exit status??

[alexphang88]

I'm quite confused by the error msg mentioned in the topic title, I get is most of the time even when my code is correct [P.S: I might be wrong >.> since I've only been studying it for 4 days, I only got to the IF statement]

Code: Select all

#include <stdio.h>

int main()
{
  int num;

  printf("Please enter a number: ");
 
  scanf("%d", &num); /*You pressed enter here . . .*/
 
  if(0<num, num<5){/* || means or, 0<num<5 is the same as 0<num || num<5 ?*/
                  printf("You entered %d, this number is between 0 and 5.", num);
                 }
  else if(num>5, num<100){
                          printf("You entered %d, this number is larger than 5 but smaller than 100", num);
                      }
  else {
        printf("The number is larger than 100.");
      }
           
  getchar(); /*So you must place a getchar(); here to cancel it out?*/
  getchar();
 
}

This is the one that I wrote originally. (I'm using DEV C++) Yet when I compile and run it it displays the error msg:"Permission denied, Id returned 1 exit status".

Then I tried to change the layout a bit so that it looked like this

Code: Select all

#include <stdio.h>

int main()
{
  int num;

  printf("Please enter a number: ");
 
  scanf("%d", &num); /*You pressed enter here . . .*/
 
  if(0<num, num<5){/* || means or, 0<num<5 is the same as 0<num || num<5 ?*/
  printf("You entered %d, this number is between 0 and 5.", num);
  }
  else if(num>5, num<100){
  printf("You entered %d, this number is larger than 5 but smaller than 100", num);
  }
  else {
  printf("The number is larger than 100.");
  }
           
  getchar(); /*So you must place a getchar(); here to cancel it out?*/
  getchar();
 
}

And then the code worked fine?! O.o
and then I tried (by coincidence) to only pull the last most curly bracket up one line, and it worked!?

Code: Select all

#include <stdio.h>

int main()
{
  int num;

  printf("Please enter a number: ");
 
  scanf("%d", &num); /*You pressed enter here . . .*/
 
  if(0<num, num<5){/* || means or, 0<num<5 is the same as 0<num || num<5 ?*/
                  printf("You entered %d, this number is between 0 and 5.", num);
                 }
  else if(num>5, num<100){
                          printf("You entered %d, this number is larger than 5 but smaller than 100", num);
                      }
  else {
        printf("The number is larger than 100.");
      }
           
  getchar(); /*So you must place a getchar(); here to cancel it out?*/
  getchar();
}

I tend to get this msg a lot when I got my codes correct sometimes, what is causing this? Or is the problem really lie in the code I use? Thanks in advance for any help, have a nice day.

[dellex]

No, the problem is not the code.

I'm assuming you're using windows.
(If you were using linux, it could be a problem with permissions.)

The most possible explanation is that your program is already running when you try to re-build it (actually re-link it, as 'ld' refers to the linker). Make sure that every time you run the program, it exits normally.... btw, what's the deal with the double "getchar()"?

---

Code: Select all

/* || means or, 0<num<5 is the same as 0<num || num<5 ?*/

yes, "||" means "OR", but "0<num<5" is translated to "0<num && num<5" where "&&" is the "AND" operator.

[fashizzlepop]

Code: Select all

/* || means or, 0<num<5 is the same as 0<num || num<5 ?*/


False. You mean && not ||. "0<num || num<5" will accept any number as 16 is greater than 0 or -20 is less than 5.

[alexphang88]

I see, so basically I need to run the task manager to check if my stuff is running, then compile and run again?

Btw, I always see this return 0; thing appearing at the end of each code in the tutorial, although it said it is to return a 0 back to the console so that it knows the program ran successfully, but without it the program still works?!(some tutorial's code doesn't include it) and also, isn't returning a 0 means FALSE?

[neuromanta]

I see, so basically I need to run the task manager to check if my stuff is running, then compile and run again?

Btw, I always see this return 0; thing appearing at the end of each code in the tutorial, although it said it is to return a 0 back to the console so that it knows the program ran successfully, but without it the program still works?!(some tutorial's code doesn't include it) and also, isn't returning a 0 means FALSE?

Returning a 0 at the end of the program (provided that there were no error) is a Unix convention. When you write programs for Linux, you should follow this convention (that's why the main() function must return an int, not void). It helps your program to report back to the operating system (if you return a number other than 0, it means some kind of error).
False meaning 0 and True meaning 1 is just another convention (some people doesn't agree with it btw, me included).

[apples]

Returning a 0 at the end of the program (provided that there were no error) is a Unix convention

No, it is a C convention. Returning 0 upon success is a valid course of action for any conforming C implementation.

[neuromanta]

Returning a 0 at the end of the program (provided that there were no error) is a Unix convention

No, it is a C convention. Returning 0 upon success is a valid course of action for any conforming C implementation.

We both are right, yet neither of us are. Unix and C was developed parallel to each other, in fact, C was created for Unix. So it's hard to tell in which one this convention was first. But it's a convention in both of them (do you think that you shouldn't return 0 in a Unix-like environment if the program is written in another language?).