The viewstate of a page contains (as the name suggests) the state of a form. It fills in the form for you after a postback event. Some googling tells me it's a base64 encoded string.
I'm just wondering in what scenario you need to decrypt it.
have you considered running the linux server as a virtual machine? I think it's less of a hassle than dual booting + it gives you the opportunity to have both windows and linux running at the same time.
I think something went wrong in translation. The album is uploaded already. All I want to do is show the content. I chose the album to VIEW using a GET-variable (to determine which folder to open) However, playing with this GET-variable, I found out I could list directories I'm not supposed to acces...
this code is used to chose which directory to list <?php function getFirstImage($dirname) { $imageName=""; if($handle = opendir($dirname)) { while(false!== ($file = readdir($handle))) { if(!preg_match("/^[.]/",$file)){ $imageName = $file; break; } } closedir($handl...
I have this page where all the content from a directory is read and shown on screen. Ideally the directory only contains images to create a photo gallery. The directory is chosen by name (which is read from get-variable) eg: http://www.mysite.com/album?id="xyz" As it is now if i give in th...
I think it's possible to loose the get-variables alltogether if you turn it into a RESTful site. I've only taken a quick look at it, so I can't be certain.
An other cheap and legal method is setting up some virtualisation with vmware, virtualbox or stuff like that. You don't even need to buy new hardware that way.
Also setting up your own server (being physical or virtual) you learn how things work from an administrator point of view too, sorta.